There are four houses in Camp Hill School's Junior Football Competition: Seymour, Beaufort, Tudor, and Howard. Each team receives 3 points for winning a match, 1 point for drawing a match and no points for losing a match. After each team has played every other team twice, the points scored are: Tudor: 11 Beaufort: 10 Seymour: 6 Howard: 6

How many games so far have resulted in a draw? A) 3 B) 4 C) 5 D) 6 E) None of the Above

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There is a maximum of 36 points available: 12 matches:
Seymour vs. Beaufort
Seymour vs. Tudor
Seymour vs. Howard
Beaufort vs. Seymour
Beaufort vs.Tudor
Beaufort vs. Howard
Tudor vs. Seymour
Tudor vs. Beaufort
Tudor vs. Howard
Howard vs. Seymour
Howard vs. Beaufort
Howard vs. Tudor

12 Matches * 3 Points (for a win) = 36 Points
For every drawn match there are 2 points available. e.g Seymour vs. Beaufort, Seymour get 1 point; Beaufort get 1 point. 1+1=2 Points
The teams have got 33 points altogether(11+10+6+6 = 33) which would make: 9 matches won = 27 points and 3 matches drawn = 6 points 27+6 = 33 points (the number that the teams got altogether which means that this is correct).

Frustratingly Fun Football QuestionThere are

fourhouses in Camp Hill School's Junior Football Competition:Seymour, Beaufort, Tudor, and Howard.

Each team receives

3 points for winninga match,1 point for drawinga match andno points for losinga match.After each team has played every other team

twice, the points scored are:Tudor: 11

Beaufort: 10

Seymour: 6

Howard: 6

How many games so far have resulted in a draw?A)3B)4C)5D)6E)None of the Above

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